A bag contains 10 counters. 6 of them are white. a counter is taken at random and not replaced. A second counter is taken out of the bag at random. Calculate the probability that only one of the two counters are white.PLEASE HELP!!

Step-by-step explanation:Given: There are 10 counters. 6 of the counters are white. Two counters are drawn one after another without replacement. To Find: The probability that only one of the two counters is white Explanation: P(Only one of the two counters is white) = P(white) x P( not white) + P(not white) x p(white) Solution: P(Only one of the two counters is white) = 6/10 x 4/9 + 4/10 x 6/9 P(Only one of the two counters is white) = 4/15 + 4/15 P(Only one of the two counters is white) = 8/15 Answer: The probability is 8/15