For ΔABC, ∠A = 8x - 10, ∠B = 10x - 40, and ∠C = 3x + 20. If ΔABC undergoes a dilation by a scale factor of 1 2 to create ΔA'B'C' with ∠A' = 6x + 10, ∠B' = 70 - x, and ∠C' = 10x 2 , which confirms that ΔABC∼ΔA'B'C by the AA criterion? A) ∠A = ∠A' = 70° and ∠B = ∠B' = 60° B) ∠A = ∠A' = 35° and ∠B = ∠B' = 30° C) ∠B = ∠B' = 54° and ∠C = ∠C' = 40° D) ∠A = ∠A' = 76° and ∠C = ∠C' = 53°
Accepted Solution
A:
If the triangles ABC and A'B'C' are similar, then angle A = angle A' 8x-10 = 6x+10 8x-6x = 10+10 2x = 20 x = 20/2 x = 10
So angle A is angle A = 8x-10 angle A = 8*10-10 angle A = 80-10 angle A = 70 making that the measure of angle A' as well