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Multiply. β3/7xy(β35x^3y^2)This is REALLY IMPORTANT I NEED IT DONE BY 2/4/2018 1:00THANK YOU (SHOW...
4 months ago
Q:
Multiply. β3/7xy(β35x^3y^2)This is REALLY IMPORTANT I NEED IT DONE BY 2/4/2018 1:00THANK YOU (SHOW YOUR WORK OR NO POINTS)
Accepted Solution
A:
-3/7xy(-35x^3y^2)
-3/7 * -35 = 105/7 = 15
x * x^3 = x^4
y * y^2 = y^3
so u r left with : 15x^4y^3 <==